The correct statement(s) about $C_{5} H_{11} B r$ is/are:

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Two out of the all structural isomers of $C_{5} H_{11} B r$ are inert towards $E_{2}$ reaction

Total 8 structural isomers are possible for $C_{5} H_{11} B r$

Only one out of all structural isomers of $C_{5} H_{11} B r$ gives three products in $E_{2}$ reaction

Only two out of all structural isomers of $C_{5} H_{11} B r$ produce alkene which can show geometrical isomerism $E_{2}$ reaction.

answer is A, C, D.

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Detailed Solution

Total 8 structural isomers.
(Viii) is inert towards E – 2
(ii) gives three alkenes in E – 2

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