The correct statement(s) about  $C_5{H}_{11}Br$  is/are:

Two out of the all structural isomers of $C_5{H}_{11}Br$ are inert towards $E_2$ reaction 

Total 8 structural isomers are possible for $C_5{H}_{11}Br$ 

Only one out of all structural isomers of $C_5{H}_{11}Br$ gives three products in $E_2$ reaction

Only two out of all structural isomers of  $C_5{H}_{11}Br$ produce alkene which can show geometrical isomerism $E_2$ reaction.