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The correct statement(s) about the oxoacids, $H C l O_{4}$ and $H C l O$ , is (are) :

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$H C l O_{4}$ is more acidic than $H C l O$ because of the resonance stabilization of its anion

$H C l O_{4}$ is formed in the reaction between $C l_{2}$ and $H_{2} O$ .

The central atom in both $H C l O_{4}$ and $H C l O$ is $s p^{3}$ hybridized

The conjugate base of $H C l O_{4}$ is weaker base than $H_{2} O$

answer is A, C, D.

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Detailed Solution

(A) $H C l O_{4} ⇌ H^{+} + C l O_{4}^{-}$ $C l O_{4}^{-}$ is resonance stability
$H C l O ⇌ H^{+} + C l O^{-}$
$∴ H C l O_{4}$ is more acidic than $H C l O$ .
(B) $C l_{2} + H_{2} O \to H C l O + H C l$

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