The correct statements about the structures of $H_{2} O_{2}$ , $O_{2} F_{2}$ and ${OF}_{2}$ is/are :

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$H_{2} O_{2}, O_{2} F_{2}, {OF}_{2}$ are polar compounds

$d_{O - O}$ of $H_{2} O_{2} > d_{O - O}$ of $O_{2} F_{2}$

$d_{O - F}$ of ${OF}_{2} > d_{O - F}$ of $O_{2} F_{2}$

the strength of $O - O$ bond in $O_{2} F_{2}$ is greater than that of $H_{2} O_{2}$

answer is A, B, D.

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Detailed Solution

$H_{2} O_{2}, O_{2} F_{2}, {OF}_{2}$ has a bent shape and it's a polar molecule.

The strength of $O - O$ bond in $O_{2} F_{2}$ is greater than that of $H_{2} O_{2}$ . This is because the high electronegativity of attached with F-atoms. H₂O₂ is a type of covalent compound.

Here, option A , B and D are correct.

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