The correct statements among (a) to (d) are :1. Saline hydrides produce H2 gas when reacted with H2O2. Reaction of LiAlH4 with BF3 leads to B2H63. PH3 and CH4 are electron rich and electron precise hydrides, respectively4. HF and CH4 are called as molecular hydrides

MH+H2O⟶MO+H24AlH4+4BF3→ Ether2B2H6+3LiF+3AlF3PH3 is electron rich and CH4 is electron precise hydride CH4 both are molecular hydride but HF is covalent hydride.

The correct statements among (a) to (d) are :1. Saline hydrides produce H2 gas when reacted with H2O2. Reaction of LiAlH4 with BF3 leads to B2H63. PH3 and CH4 are electron rich and electron precise hydrides, respectively4. HF and CH4 are called as molecular hydrides

MH+H2O⟶MO+H24AlH4+4BF3→ Ether2B2H6+3LiF+3AlF3PH3 is electron rich and CH4 is electron precise hydride CH4 both are molecular hydride but HF is covalent hydride.

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The correct statements among (a) to (d) are :
1. Saline hydrides produce H₂ gas when reacted with H₂O
2. Reaction of LiAlH₄ with BF₃leads to B₂H₆
3. PH₃ and CH₄ are electron rich and electron precise hydrides, respectively
4. HF and CH₄ are called as molecular hydrides

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(1), (2), (3) and (4)

(1), (3) and (4) only

(1), (2) and (3) only

(3) and (4) only

answer is B.

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Detailed Solution

$\begin{array}{l} MH + H_{2} O ⟶ MO + H_{2} \\ 4 {AlH}_{4} + 4 {BF}_{3} \overset{Ether}{\to} 2 B_{2} H_{6} + 3 LiF + 3 {AlF}_{3} \end{array}$
PH₃ is electron rich and CH₄ is electron precise hydride CH₄ both are molecular hydride but HF is covalent hydride.