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The correct statements is/ are :

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${BeF}_{2}$ is more soluble in water than ${BaF}_{2}$

${BiF}_{5}$ exists but ${Bil}_{5}$ does not exist

${BaCO}_{3}$ is less thermally, stable than ${BaCO}_{3}$

AgF is colourless while AgI is coloured, due to higher polarisability of $F^{-}$

answer is A, C, D.

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Detailed Solution

${BeF}_{2}$ is higher stable compare to ${BaF}_{2}$ as fluoride ion is a small anion and small anion is stabilised by small cation.

Bismuth is the element of group 15. Down the group, the +3 oxidation state becomes more stable due to the inert pair effect. Here, statement given in option B is incorrect.

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