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The correct statements regarding Ellingham's diagram are

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below 710^oC, CO is a more effective reducing agent than carbon

it gives a clear explanation of need for the conversion of metal sulphide to corresponding oxides before reduction

metal oxides have less negative value of $∆ G^{o}$ as compared to CO₂ hence, oxidation of metal sulphides to oxides is not favourable

a metal can reduce the oxide of only those metal which lies above it in the Ellingham diagram

answer is A.

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Detailed Solution

$∆ G^{o}$ of metal oxides is lower than that of CO₂ hence, oxidation of metal sulphide to metal oxide is favourable.

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