The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$Δ H < 0$ and $Δ S > 0$

$Δ H > 0$ and $Δ S < 0$

$Δ H < 0$ and $Δ S = 0$

$Δ H < 0$ and $Δ S < 0$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

$∆ H < 0$ and $∆ S > 0$

Under these conditions, $Δ G = Δ H - T Δ S < 0$

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is $∆ H < 0$ and $∆ S > 0$

Under these conditions, $Δ G = Δ H - T Δ S < 0$

Note: for spontaneous reactions, $Δ G < 0$ , for non spontaneous reactions, $Δ G > 0$ , for reactions at equilibrium, $Δ G = 0$

Hence the correct answer is (C) $Δ H < 0$ and $Δ S > 0$ .

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE