The correct value of cell potential in volt for the reaction that occurs when the following two half cells are connected, is
$\begin{array}{l}{\mathrm{Fe}}_{\text{(aq) }}^{2+}+2{\mathrm{e}}^{-}\to \mathrm{Fe}\left(\mathrm{s}\right),{\mathrm{E}}^{\circ }=-0.44\mathrm{V}\\ {\mathrm{Cr}}_2{\mathrm{O}}_7^{2-}\text{ (aq) }+14{\mathrm{H}}^{+}+6{\mathrm{e}}^{-}\to 2{\mathrm{Cr}}^{3+}+7{\mathrm{H}}_2\mathrm{O},\\ {\mathrm{E}}^{\circ }=+1.33\mathrm{V}\end{array}$