Q.

The correct value of emf of cell is given by

(i) Ecell=EOPanodeERP cathode

(ii) Ecell=EOPanode+ERP cathode

(iii) Ecell=ERPanode+ERP cathode

(iv) Ecell=EOPanodeEOP cathode

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a

(iii) and (iv)

b

(ii) and (iv)

c

(iii) and (i)

d

(i) and (ii)

answer is D.

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Detailed Solution

Ecell=EOPanode+ERPCathode=EOPanodeEOPcathode

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The correct value of emf of cell is given by(i) Ecell=EOP anode−ERP cathode(ii) Ecell=EOP anode+ERP cathode(iii) Ecell=ERP anode+ERP cathode(iv) Ecell=EOP anode−EOP cathode