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Q.

The cosx+xsinxx(x+cosx)dx=

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a

log|x(x+cosx)|+c

b

logxx+cosx+c

c

logx+cosxx+c

d

log|x(cosx+xsinx)|+c

answer is C.

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Detailed Solution

cosx+x+xsinxxx(x+cosx)dx =cosx+xx(x+cosx)dx+x(sinx1)x(x+cosx)dx=1xdx+sinx1x+cosxdx
=logxlog(x+cosx)+c=logxx+cosx+c

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