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The couple acting on a bar magnet of pole strength 2 Am when kept in a magnetic field of intensity 10 A/m, such that axis of the magnet makes an angle 30⁰ with the direction of the field is 80 $\times$ 10^-7 Nm . The distance between the poles of the magnet is

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$\frac{2}{π} m$

$\frac{π}{2} m$

63.36 m

$\frac{1}{2 π} m$

answer is A.

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Detailed Solution

$C = M B \sin θ = m \times 2 l \times μ_{0} \times H \times \sin θ$

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