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The cricket ball of mass $70 g$ moving with velocity of $0.5 m / s$ is stopped by a player in $0.5 second$ . What will be the force applied by the player to stop the ball?

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0.07 N

0.7 N

1 N

2 N

answer is A.

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Detailed Solution

The force acting on the cricket ball is

0.07 N

.
Given data in the problem,
Velocity of cricket ball,

u = 0.5 m / s

Time,

t = 0.5 s

Mass of cricket ball,

m = 70 g

And 70 g can be written as 0.07 kg
Assuming

v = 0

By using the first equation of motion

v = u + at

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

\Rightarrow 0 = 0.5 + a \times 0.5

\Rightarrow a = - 0.5 / 0.5

\Rightarrow a = - 1 m s^{- 2}

(Negative sign shows that the acceleration is in negative or say retardation)
so, the force exerted in the cricket ball is given by

F = ma

\Rightarrow F = 0.07 \times (1)

\Rightarrow F = 0.07 N

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