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Q.

The cryoscopy constant of water is 1.86K kg mol-1. A 0.01 molal acetic acid solution produces a depression of 0.0194°C in the freezing point. The degree of dissociation of acetic acid is.

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a

zero

b

0.072

c

1

d

0.043

answer is B.

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Detailed Solution

∆Tf = i.Kf.m, then  i = 0.0194 / 1.86 × 0.01  = 1.043
Degree of dissociation = α = (i-1) / (n-1)  = (1.043-1) / (2-1) = 0.043

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