The crystal field stabilization energy ( CFSE) is the highest for

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${[Co (NCS)_{4}]}^{2 -}$

${[Co {({NH}_{3})}_{6}]}^{3 +}$

${[{CoF}_{4}]}^{2 -}$

${[{CoCl}_{4}]}^{2 -}$

answer is C.

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Detailed Solution

Higher the oxidation state of the metal, greater the crystal field splitting energy. In options (a), (b) and (d), Co is present in +2 oxidation state and in (c) it is present in +3 oxidation state and hence has a higher value of CFSE.

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