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Q.

The crystal field stabilization energy of $[C o {(N H_{3})}_{6}] C l_{3}$ is $- x Δ_{0}$ then $| 10 x |$ is $A B$ . Sum of $A + B$ is

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answer is 6.

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Detailed Solution

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$C o^{3 +} \to s^{0} d^{6} (strong ƒield) \to t_{2 g}^{6} e g^{0} C F S E = [0.6 n_{e g} - 0.4 n_{t_{2 g}}] Δ_{0} = [0.6 (0) - 0.4 (6)] Δ_{0} = - 2.4 Δ_{0} x = 24.00$

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