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The cubic unit cell of aluminium (molar mass $27.0 g {mol}^{- 1}$ ) has an edge length of 405 pm. Its density is 2.70 g ${cm}^{- 3} .$ The type of unit cell is

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An Intiative by Sri Chaitanya

Primitive

Face-centred

Body-centred

End-centred

answer is B.

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Detailed Solution

$N = ρ a^{3} (\frac{N_{A}}{M}) N = (2.70 g {cm}^{- 3}) {(405 \times 10^{- 10} cm)}^{3} (\frac{6.022 \times 10^{23} {mol}^{- 1}}{27.0 g {mol}^{- 1}}) N = 4$

The unit cell is face-centred cube.

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