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Q.

The cubical container ABCDEFGH which is completely filled with an ideal (non-viscous and incompressible) fluid, moves in a gravity free space with an acceleration of $a = a_{0} (\hat{i} - \hat{j} + \hat{k})$ where $a_{0}$ is a positive constant. Then the only point in the container where pressure can be zero is:

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a

H

b

B

c

C

d

E

answer is D.

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Detailed Solution

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Acceleration of container is
$a = a_{0} (\hat{i} - \hat{j} + \hat{k})$
As there is no gravity; the pressure difference will be only due to the acceleration. All points other than point ‘H’, are acted upon by a pseudo force. Hence, at point ‘H’ pressure developed is zero.

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