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Q.

The current density in a wire of radius a varies with radial distance r as

J=kr2 , where k is a constant.

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a

The field at a distance r > a is B=μ0ka44r

b

The field at a distance r < a is B=μ0kr34

c

Total current passing through the cross section of the wire is I=3πka32

d

Total current passing through the cross section of the wire is I=πka42

answer is A, C, D.

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Detailed Solution

Ans: ACD

Question Image

dI = JdA

dI=kr2(2πrdr)

I=2πk0ar3dr    I=12πka4

Further, field for r > a is

B=μ0I2πr=μ0ka44r

And field for r < a is

B=μ0(πkr42)2πr=14μ0kr3

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