The current flowing through a conductor connected across a source is 2A and 1.2A at 0∘C and 100∘C . respectively. The current flowing through the conductor at 50∘C will be ____ ×102 mA.

Current at 0∘C, =VR0=2Current at 100∘C, =VR0(1+100α)=1.2Dividing,(1+100α)=21.2⇒∝=2300°C-1Current at 50∘C=VR0(1+50)α=21+50×2300=1.5 A=15×102 mA.

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

The current flowing through a conductor connected across a source is 2A and 1.2A at $0^{\circ} C$ and $100^{\circ} C$ . respectively. The current flowing through the conductor at $50^{\circ} C$ will be ____ $\times 10^{2} mA .$

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 15.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Current at $0^{\circ} C$ , $\begin{array}{l} = \frac{V}{R_{0}} = 2 \end{array}$

Current at $100^{\circ} C$ , $= \frac{V}{R_{0} (1 + 100 α)} = 1.2$

Dividing,

$(1 + 100 α) = \frac{2}{1.2} \Rightarrow \propto = \frac{2}{300} ° C^{- 1}$

Current at $50^{\circ} C$

$= \frac{V}{R_{0} (1 + 50) α} = \frac{2}{1 + 50 \times \frac{2}{300}} = 1.5 A$

$= 15 \times 10^{2} mA .$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE