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The current flowing through an ac circuit is given by $I = 5 \sin (120 πt) Amp .$ How long will the current take to reach the peak value starting from zero?

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$\frac{1}{60} s$

$60 s$

$\frac{1}{240} s$

$\frac{1}{120} s$

answer is D.

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Detailed Solution

$i = 5 \sin (120 πt)$

$ω = 120 π \Rightarrow T = \frac{2 π}{ω} = \frac{2 π}{120 π}$

$T = \frac{1}{60} \sec$

Time taken by current to reach peak value from zero is T/4

$t = \frac{1}{240} \sec$

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