The current flowing through R2 is :

Equivalent resistance =2Ω⇒current from battery =82=4ASo, 2A flows through R5Which splits in 2:1 ratio between R7 and R4Further it splits in 1:1 ratio between R3 and R2So, current through R2=2×13×12=13

The current flowing through R2 is :

Equivalent resistance =2Ω⇒current from battery =82=4ASo, 2A flows through R5Which splits in 2:1 ratio between R7 and R4Further it splits in 1:1 ratio between R3 and R2So, current through R2=2×13×12=13

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The current flowing through R₂ is :

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$\frac{1}{3} A$

$\frac{2}{3} A$

$\frac{1}{2} A$

$\frac{1}{4} A$

answer is C.

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Detailed Solution

Equivalent resistance $= 2 Ω$
$\Rightarrow$ current from battery $= \frac{8}{2} = 4 A$
So, 2A flows through R₅
Which splits in 2:1 ratio between R₇ and R₄
Further it splits in 1:1 ratio between R₃ and R₂
So, current through $R_{2} = 2 \times \frac{1}{3} \times \frac{1}{2} = \frac{1}{3}$