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The current gain for a transistor working as common-base amplifier is 0.96. If the emitter current is 7.2 mA, then base current is

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0.35 mA

0.29 mA

0.39 mA

0.43 mA

answer is B.

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Detailed Solution

$α = \frac{I_{C}}{I_{E}} ∴ I_{C} = {αI}_{E} = 0 .96 \times 7 .2 = 6 .91 mA Now, I_{E} = I_{C} + I_{B} ∴ I_{B} = I_{E} - I_{C} = 7 .2 - 6 .91 = 0 .29 mA$

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