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The current ‘i’ in the circuit as shown in fig.

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$\frac{1}{3} A$

1.5A

answer is D.

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Detailed Solution

BC & AC are in series.

This combination is parallel to AB;

$R_{e f f} = \frac{(3 + 3) \times 3}{3 + 3 + 3} = 2 Ω$

$I = V / R_{eq} = \frac{3}{2} A$

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