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Q.

The current in a conductor varies with time ‘t’ as I = 3t + 4t2 . Where I in amp and t in sec. The electric charge flows through the section of the conductor between t = 1s and t = 3s

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a

3140C

b

1403C

c

314C

d

143C

answer is C.

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Detailed Solution

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I=dqdt;dq=Idt;∫dq=∫13 Idt=∫13 3t+4t2dt=3t22+4×t33=32(3)2+43(3)3−32(1)2−43(1)3=1403C

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