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The current in the primary coil of a pair of coils changes from 7 A to 3 A in 0.04 s. The mutual inductance between the two coils is 0.5 H. The induced emf in the secondary coil is –

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50 V

75 V

100 V

220 V

answer is A.

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Detailed Solution

$ε = M |\frac{dI}{dt}| = 0 .5 |\frac{(3 - 7)}{0 .04}| = 0 .5 \times \frac{4}{0 .04} = 50 V$

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