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Q.

The current in the primary coil of a pair of coils changes from 7 A to 3 A in 0.04 s. The mutual inductance between the two coils is 0.5 H. The induced emf in the secondary coil is –

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a

50 V

b

75 V

c

100 V

d

220 V

answer is A.

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Detailed Solution

ε=MdIdt=0.5(3−7)0.04=0.5×40.04=50V

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