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Q.

The current in the windings on a toroid is 2.0 A. There are 400 turns and the mean circumferential length is 40 cm. If the inside magnetic field is 1.0 T, the relative permeability is near about 

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a

100

b

400

c

200

d

300

answer is D.

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Detailed Solution

B=μ0μrNi2πrin a medium

Substituting the value in above formula

I=μrμ0(400)(2)0.4.alsoμ0=4π×107 alsoμ0=4π×107 henceμr=0.44π×107×400×2=400 henceμr=400 

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