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Q.

The current required to be passed through a solenoid of 20 cm length and 100 turns in order to demagnetized a bar magnet of magnetic intensity $2.4 \times 10^{3} A m^{- 1}$ is
(Round off to the nearest integer)

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answer is 5.

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Detailed Solution

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$H = n i = \frac{N}{l} i$

$i = \frac{H l}{N} = \frac{2.4 \times 10^{3} \times 0.2}{100} = 4.8 A$

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