The current sensitivity of moving coil galvanometer is increased by 25%. This increase is achieved only by changing in the number of turns of coils and area of cross section of the wire while keeping the resistance of galvanometer coil constant. The percentage change in the voltage sensitivity will be

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-25%

-50%

+25%

Zero

answer is C.

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Detailed Solution

$C_{S} = \frac{BAN}{k}; V_{S} = \frac{BAN}{kG}$

$As, G = constant$
$\Rightarrow %$ change in voltage sensitivity = $%$ change in current sensitivity
$= + 25 %$

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