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Q.

The current through a 4.6H inductor is shown in the following graph. The induced emf during the time interval t=5 milli sec to 6 milli sec will be ________×103V.

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answer is 23.

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Detailed Solution

didt=−(slope   of  the   line  BC)

Hence induced emf =e=−Ldidt=4.6×510-3=23×103V

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