The curved surface area of a frustum cone is 25 mm2 . The larger circle area is12mm2.The total surface area is350mm2Find the smaller circle area of a cone Sub Grade: 9

Area of bigger circle = R212= R2R2= 12 (1)CSA of frustum cone =(r+R)h25 =(r+R)n(r+R)h = 25 (2)Given TSA = 350mm2[(r+R)h+r2+R2]= 350(R+r) h+r2+R2= 350 (3)Put the value of equation (1) and (2)In equation (3)35+r2+12= 350r2= 350-(35+12)r2= 313Area of smaller circle =r2= 22/7*313= 313 mm2

The curved surface area of a frustum cone is 25 mm2 . The larger circle area is12mm2.The total surface area is350mm2Find the smaller circle area of a cone Sub Grade: 9

Area of bigger circle = R212= R2R2= 12 (1)CSA of frustum cone =(r+R)h25 =(r+R)n(r+R)h = 25 (2)Given TSA = 350mm2[(r+R)h+r2+R2]= 350(R+r) h+r2+R2= 350 (3)Put the value of equation (1) and (2)In equation (3)35+r2+12= 350r2= 350-(35+12)r2= 313Area of smaller circle =r2= 22/7*313= 313 mm2

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The curved surface area of a frustum cone is 25 𝝿mm2 . The larger circle area is12𝝿mm2.The total surface area is350𝝿mm2Find the smaller circle area of a cone

Sub Grade: 9

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313mm2

323mm2

333𝝿mm2

313𝝿mm2

answer is D.

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Detailed Solution

Area of bigger circle = 𝝿R2
12𝝿= 𝝿R2
R2= 12 (1)
CSA of frustum cone =𝝿(r+R)h
25 𝝿=(r+R)n
(r+R)h = 25 (2)
Given TSA = 350𝝿mm2
[(r+R)h+r2+R2]= 350𝝿
(R+r) h+r2+R2= 350 (3)
Put the value of equation (1) and (2)
In equation (3)
35+r2+12= 350
r2= 350-(35+12)
r2= 313
Area of smaller circle =𝝿r2
= 22/7*313
= 313 𝝿mm2

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