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The curved surface area of right circular cylinder inscribed in a sphere of radius 22cm is maximum then height of the cylinder will be

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$\frac{11}{\sqrt{2}} c m$

$(0.11) \sqrt{2} m$

$11 \sqrt{2} c m$

$(0.22) \sqrt{2} m$

answer is C.

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Detailed Solution

$H = \sqrt{2} R = \sqrt{2} (22) c m = \sqrt{2} . \frac{22}{100} m = (0.22) \sqrt{2} m$

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