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Q.

The curves x2+y2+6x-24y+72=0 and x2-y2+6x+16y-46=0 intersect in four point P,Q, R and S lying on a parabola. Let A be the focus of the parabola, then

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a

length of latusrectum is 8

b

Equation of directrix is y+1=0

c

coordinates of A are (-3, 2)

d

vertex of the parabola is at (-3, 1)

answer is C, D.

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Detailed Solution

Add the two curve equations
2x2 + 12x - 8y + 26 = 0
x2 + 6x + 13 = 4y
(x + 3)2 = 4(y - 1)

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