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Q.

The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resistor of 40  Ω is ______ mA.

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answer is 4.

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Detailed Solution

D1 : conducting
D2 : open circuit

⇒    i=1−0.660+40A=0.4100A

⇒    i=4  mA

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The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resistor of 40  Ω is ______ mA.