The d-electron configuration of $[R u {(e n)}_{3}] C l_{2}$ and $[F e {(H_{2} O)}_{6}] C l_{2}$ , respectively are

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$t_{2 g}^{6} e_{g}^{0}$ and $t_{2 g}^{4} e_{g}^{2}$

$t_{2 g}^{4} e_{g}^{2}$ and $t_{2 g}^{4} e_{g}^{2}$

$t_{2 g}^{6} e_{g}^{0}$ and $t_{2 g}^{6} e_{g}^{0}$

$t_{2 g}^{4} e_{g}^{2}$ and $t_{2 g}^{4} e_{g}^{0}$

answer is A.

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Detailed Solution

$[R u {(e n)}_{3}] C l_{2}$ $[F e {(H_{2} O)}_{6}] C l_{2}$

$R u = [K r] 4 d^{6} 5 s^{2}$ $F e^{2 +} = [A r] 3 d^{6} 5 s^{o}$

$R u^{2 +} = [L r] 4 d^{6} 5 s^{o}$

$t_{2 g}^{2, 2, 2} e_{g}^{0, 0}$ $t_{2 g}^{2, 1, 1,} e_{g}^{1, 1}$

Inner orbital complex will be formed

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