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The d-electron configuration of ${[C o {(N H_{3})}_{6}]}^{+ 3}$ and ${[F e F_{6}]}^{- 3}$ respectively are

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$t_{2} g^{6} {eg}^{0}$ and $t_{2} g^{3} {eg}^{2}$

$t_{2} g^{3} {eg}^{3}$ and $t_{2} g^{3} {eg}^{2}$

$t_{2} g^{4} {eg}^{2}$ and $t_{2} g^{5} {eg}^{0}$

$t_{2} g^{6} {eg}^{0}$ and $t_{2} g^{5} {eg}^{0}$

answer is C.

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Detailed Solution

$C o^{+ 3} - 3 d^{7} 4 s^{2} t_{2} g^{6} e g^{0} \underset{d^{2} s p^{3}}{\underset{⏟}{3 d^{6} 4 s^{0} 4 p^{0}}}$

$F e^{+ 3} - \underset{d^{5}}{W . L} : t_{2} g^{3} e g^{2}$

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