The dark purple colour of $K M n O_{4}$ disappears in the titration with oxalic acid in acidic medium the overall change in the oxidation number of manganese in the reaction

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answer is A.

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Detailed Solution

$2 {KM}^{+ 7} {no}_{4} + 3 H_{2} {So}_{4} + 5 H_{2} C_{2} O_{4} \to K_{2} {So}_{4} + 2 M^{+ 2} n {So}_{4} + 10 {Co}_{2} + 8 H_{2} O$ $+ 7 \to + 2 = 5 e^{-}$

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