The de – Broglie wavelength of a car of mass 1000 kg and velocity 36 km/h is   $(h=6.63\times {10}^{-34}Js)$

de – Broglie equation is  $\lambda =\frac{h}{mv}$

Given, m = 1000 kg and  v = 36 km/ h $=\frac{36\times 1000}{60\times 60}=10m/s$

On putting values, $\lambda =\frac{6.626\times {10}^{-34}}{1000\times 10}$

                      $=6.626\times {10}^{-38}m$