The de-Broglie wavelength associated with an electron, accelerated by a potential difference of $81 V$ is given by $\frac{x}{100} \overset{\circ}{A}$ then $x$ = __________ .
[Round-off to the nearest integer]

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answer is 136.

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Detailed Solution

$\begin{array}{l} λ = \frac{1.23 nm}{\sqrt{V}} \\ V = 81 V \\ λ = \frac{1.23}{\sqrt{81}} \times 10^{- 9} = 1.36 \overset{\circ}{A} = \frac{136}{100} \overset{\circ}{A} \\ ∴ x = 136 \end{array}$

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