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Q.

The de-Broglie wavelength associated with an electron accelerated by a potential of 64 V is [Manipal 2015]

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a

0.153 nm

b

0.613 nm

c

1.22 nm

d

0.302 nm

answer is A.

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Detailed Solution

The de-Broglie wavelength of electron associated with voltage is given by

$λ = \frac{1.227}{\sqrt{V}} \cdot nm = \frac{1.227}{\sqrt{64}} nm = 0.153 nm$

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