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The de- Broglie wavelength of a particle of mass 6.63 g moving with a velocity of $100 m s^{- 1}$ is

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$10^{- 33} m$

$10^{- 35} m$

$10^{- 31} m$

$10^{- 25} m$

answer is A.

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Detailed Solution

$λ = \frac{h}{m υ} = \frac{(6.626 \times 10^{- 34} J s)}{(6.63 \times 10^{- 3} k g) (100 m s^{- 1})} = 10^{- 33} m$

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