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The de Broglie wavelength of a tennis of mass 60 g moving, with a velocity of 10 metres per second is approximately Planck’s constant, $h = 6.63 \times 10^{- 34}$ Js

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$10^{- 22} m$

$10^{- 31} m$

$10^{- 30} m$

$10^{- 33} m$

answer is D.

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Detailed Solution

$λ = \frac{h}{m v} = \frac{6.6 \times 10^{- 34}}{60 \times 10^{- 3} \times 10} = 10^{- 33} m$

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