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Questions  

The de Broglie wavelength of an electron in the 4th Bohr orbit of hydrogen is :

a
2πao
b
8πao
c
4πao
d
6πao

detailed solution

Correct option is B

According to Bohr's and de-Broglie concept;

2πr = λ=2πr/n=2πao×nZ (r=ao×n2Z ; ao=radius of 1st orbit) for n= 4  λ4= 8πao

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