The decimal form of $\frac{129}{2^2{5}^7{7}^5}$ is

If the decimal expansion denominator is in the form $2^m\times 2^n$ then it is terminating and if not then it is non-terminating.

In the decimal expansion $\frac{129}{2^2{5}^7{7}^5}$ the denominator also has a multiple of 7.

When a number with 9 in its units place is divided by 7, the numbers after the decimal are not repeated.

Therefore, we can say that the number is a non-terminating and non-repeating number.