The decomposition of Nitrogen pentoxide is given as $2 N_{2} O_{5} \to 4 N O_{2} + O_{2} .$ The rates of reaction are $\frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]$ , $\frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}]$ and $\frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}] .$ Then the relation between $K_{1}, K_{2} & K_{3}$ is:

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$4 K_{1} = 2 K_{2} = K_{3}$

$2 K_{1} = K_{2} = 4 K_{3}$

$K_{1} = K_{2} = K_{3}$

$K_{1} = 2 K_{2} = 4 K_{3}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$

$r = \frac{- 1}{2} \frac{d [N_{2} O_{5}]}{d t} = + \frac{1}{4} \frac{d [N O_{2}]}{d t} = + \frac{d [O_{2}]}{d t}$ .

$\Rightarrow \frac{1}{2} K_{1} [N_{2} O_{5}] = \frac{1}{4} K_{2} [N_{2} O_{5}] = K_{3} [N_{2} O_{5}]$

$\Rightarrow \frac{K_{1}}{2} = \frac{K_{2}}{4} = K_{3}$

$\Rightarrow 2 K_{1} = K_{2} = 4 K_{3}$

Watch 3-min video & get full concept clarity