The decomposition temperature of BaCO3 (A), MgCO3 (B) and CaCO3 (C) follow the order

As size of metal increases stability of carbonate increases Since a larger size cation will stabilise the large size anion Therefore, greater the stability greater will be decomposition temperature Decomposition temperature order:

The decomposition temperature of BaCO3 (A), MgCO3 (B) and CaCO3 (C) follow the order

As size of metal increases stability of carbonate increases Since a larger size cation will stabilise the large size anion Therefore, greater the stability greater will be decomposition temperature Decomposition temperature order:

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The decomposition temperature of BaCO₃ (A), MgCO₃ (B) and CaCO₃ (C) follow the order

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C > A > B

A > C > B

C > B > A

B > C > A

answer is B.

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Detailed Solution

$large xrightarrow{{;;BeC{O_3}; < ;MgC{O_3}; < ;CaC{O_3}; < ;SrC{O_3}; < ;BaC{O_3}}};:;Thermal;stability;order$
As size of metal increases stability of carbonate increases
Since a larger size cation will stabilise the large size anion $large left [ CO^{-2}_3 right ]$
$large Thermal;stability; propto ;frac{1}{{Decomposition}}$
Therefore, greater the stability greater will be decomposition temperature
Decomposition temperature order: $large ;BeC{O_3}; < ;mathop {MgC{O_3}}limits_B ; < ;mathop {CaC{O_3}}limits_c ; < ;SrC{O_3}; < ;mathop {BaC{O_3}}limits_A$