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Q.

The decreasing order of bond angles in ethane, ethylene, acetylene, and benzene is

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a

$C_{2} H_{6} > C_{2} H_{4} > C_{2} H_{2} > C_{6} H_{6}$

b

$C_{6} H_{6} > C_{2} H_{2} > C_{2} H_{4} > C_{2} H_{6}$

c

$C_{2} H_{6} > C_{2} H_{4} = C_{2} H_{2} > C_{6} H_{6}$

d

$C_{2} H_{2} > C_{2} H_{4} = C_{6} H_{6} > C_{2} H_{6}$

answer is C.

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Detailed Solution

Ethane have a bond angle to of $109.5 °$ .
Ethylene and benzene have same bond angle $120 °$ .
Acetylene have a bond angle to of 180⁰

Hence, the correct option (C) $C_{2} H_{2} > C_{2} H_{4} = C_{6} H_{6} > C_{2} H_{6}$ .

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