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Q.

The decreasing order of bond angles in ethane, ethylene, acetylene, and benzene is

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a

C2H6 > C2H4 > C2H2 > C6H6

b

C2H6 > C2H4 = C2H2 > C6H6

c

C2H2 > C2H4 = C6H6 > C2H6

d

C6H6 > C2H2 > C2H4 > C2H6

answer is C.

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Detailed Solution

  •  Ethane have a bond angle to of 109.5°.
  • Ethylene and benzene have same bond angle  120°. 
  • Acetylene  have a bond angle to of 1800

Hence, the correct option (C) C2H2 > C2H4 = C6H6 > C2H6 .

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