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Q.

The decreasing order of Cl-O bond energy in ClO^–, ${ClO}_{2}^{-}, {ClO}_{3}^{-}, {ClO}_{4}^{-}$ is

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a

${ClO}_{3}^{-} > {ClO}^{-} > {ClO}_{2}^{-} > {ClO}_{4}^{-}$

b

${ClO}_{4}^{-} > {ClO}_{3}^{-} > {ClO}_{2}^{-} > {ClO}^{-}$

c

${ClO}^{-} > {ClO}_{2}^{-} > {ClO}_{3}^{-} > {ClO}_{4}^{-}$

d

${ClO}_{4}^{-} > {ClO}_{2}^{-} > {ClO}_{3}^{-} > {ClO}^{-}$

answer is B.

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Detailed Solution

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Bond order of ClO⁻= 1,

Bond order of ClO₂⁻= 1.5,
Bond order of ClO₃⁻= 1.66 ,

Bond order of ClO₄⁻ = 1.75.

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