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Q.

The decreasing order of energy for the electrons represented by the following sets of quantum numbers is

1) n=4,l=0, m=0, s=±1/2    2)  n=3, l=1, m=1,s=-1/2 
3)  n=3, l=2, m=0,s=+1/2                     4)  n=3, l=0, m=0,s=-1/2

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a

4>3>2>1

b

3>1>2>4

c

1>2>3>4

d

2>1>3>4

answer is C.

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Detailed Solution

n +l value increases energy increases

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