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Q.

The decreasing order of hydration enthalpies of alkaline earth metal ions is

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a

${Be}^{2 +} > {Mg}^{2 +} > {Ca}^{2 +} > {Sr}^{2 +} > {Ba}^{2 +}$

b

${Be}^{2 +} > {Ba}^{2 +} > {Mg}^{2 +} > {Ca}^{2 +} > {Sr}^{2 +}$

c

${Ba}^{2 +} > {Sr}^{2 +} > {Ca}^{2 +} > {Mg}^{2 +} > {Be}^{2 +}$

d

${Be}^{2 +} > {Ca}^{2 +} > {Sr}^{2 +} > {Mg}^{2 +} > {Ba}^{2 +}$

answer is A.

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Detailed Solution

The smaller the size (small ionic radius) of the metal ion greater will be the hydration enthalpies.
The greater the charge density on metal ion greater will be the hydration enthalpies
Among the given metal ions, ${Be}^{2 +}$ ion is small in size. The charge on all atoms is the same but due to the smaller size of ${Be}^{2 +}$ it has greater charge density.

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The decreasing order of hydration enthalpies of alkaline earth metal ions is