Q.

The decreasing order of second ionization energy of K, Ca and Ba is

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a

Ca > Ba > K

b

Ba > K > Ca

c

K > Ca > Ba

d

K > Ba >Ca

answer is C.

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Detailed Solution

As we move down the group size increases and the electron experience less effective nuclear charge and IE decreases down the group.

 hence IE of  Ca > Ba

IE2 of K > Ca , due to noble gas configuration of K+

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